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Game Moderator Darkseeker
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My parents showed me a math riddle that I haven't been able to figure out. Basically, it's the following: Use any operator or arithmetic method to achieve find the results. You may not switch the order of the numbers around, but you can use things like addition, square roots, exponents, factorials etc. 3 7 5 = 1 3 7 5 = 2 3 7 5 = 3 3 7 5 = 4 3 7 5 = 5 3 7 5 = 6 3 7 5 = 7 3 7 5 = 8 3 7 5 = 9 3 7 5 = 10 If you can get all ten correct, then that means you're a genius :D
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Neutral
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Do we post the answers? I mean I figured it out ->-
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Game Moderator Darkseeker
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You figured it out that fast? O.o I mean, you could if you really wanted, but... probably should put a spoiler on it. You can do that by coloring your text and highlighting it the same color. Edited at March 29, 2020 02:12 PM by Vennenum
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Neutral
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Yes...? It may take a while to type it though -_- Edited at March 29, 2020 02:11 PM by Ruff Starts
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Game Moderator Darkseeker
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There's probably multiple answers out there, but you can if you want. lmao
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Neutral
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Number 1 is: 3-7 = -4 +5 = 1 will take a few minutes to type all the answers Edited at March 29, 2020 02:16 PM by Ruff Starts
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Neutral
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lol is gcd even a valid arithmetic method #1: 3 - 7 + 5 = 1 #2: (3 + 7) / 5 = 2 #3: gcd (3, (7+5)) = 3 #4: (|3! - 7!|) mod 5 = 4 #5: 3 + 7 - 5 = 5 #6: gcd (3!, (7+5)) = 6
#7: √(|3-7|) + 5 = 7 #8: (3 mod 7) + 5 = 8 #9: |3 - 7| + 5 = 9 #10: gcd ((3+7), 5!) = 10 Edited at March 29, 2020 03:35 PM by Life on Mars
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Neutral
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(3*7) mod 5=1 (3^7) mod 5=2 (3 + fact(7)) mod 5=3 sqrt(3x7-5)=4 3+(7 mod 5) = 5 3x(7-5)=6 sqrt(abs(3-7))+5=7 fact(3)+7-5=8 3^(7-5)=9 sqrt(abs(3-7))*5=10 Edited at March 29, 2020 03:28 PM by Dire
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Neutral
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Dire's officially a genius
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Neutral
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Life on Mars said: Dire's officially a genius
Thanks :) You're doing a nice job too
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